bentuk sederhana dari
[tex](2x + 1)(3x - 4) \\ a. \: 6 {x }^{2} + 5x + 4 \\ b. \: 6 {x}^{2} - 5x + 4 \\ c. \: 6 {x}^{2} + 5x - 4 \\ d. \: 6 {x}^{2} - 5x - 4[/tex]
[tex](2x + 1)(3x - 4) \\ a. \: 6 {x }^{2} + 5x + 4 \\ b. \: 6 {x}^{2} - 5x + 4 \\ c. \: 6 {x}^{2} + 5x - 4 \\ d. \: 6 {x}^{2} - 5x - 4[/tex]
Jawab:
(2x + 1)(3x - 4) = 6x² - 8x + 3x - 4
= 6x² + (-8+3)x - 4
= 6x² - 5x - 4 (d)
(2X +1) (3X -4) = 6X² (-8) +3X -4
6X² ((-8)+3) - 4 = 6X² - 5 -4
[answer.2.content]